From: "MB Software Solutions

>>> I defy anyone to recover the password from the stored value :-).

>>

>>

>> There is a big risk of collision using your method.

>> As the result set is composed of only 65128 different values,

>> it doesn't take a long time to input in the routine a string whose result

>> will be the same value as the stored one ...

> Are you saying that two different values could end up with the same

> resulting value from his algorithm?

Exactly.

You can enter 256**20 (1.461E+48) different strings, but only 65128

checksums are possible with this algorithm.

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